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Simplifying 2b2 + -11bc + 5c2 = 0 Reorder the terms: -11bc + 2b2 + 5c2 = 0 Solving -11bc + 2b2 + 5c2 = 0 Solving for variable 'b'. Factor a trinomial. (b + -5c)(2b + -1c) = 0Subproblem 1
Set the factor '(b + -5c)' equal to zero and attempt to solve: Simplifying b + -5c = 0 Solving b + -5c = 0 Move all terms containing b to the left, all other terms to the right. Add '5c' to each side of the equation. b + -5c + 5c = 0 + 5c Combine like terms: -5c + 5c = 0 b + 0 = 0 + 5c b = 0 + 5c Remove the zero: b = 5c Simplifying b = 5cSubproblem 2
Set the factor '(2b + -1c)' equal to zero and attempt to solve: Simplifying 2b + -1c = 0 Solving 2b + -1c = 0 Move all terms containing b to the left, all other terms to the right. Add 'c' to each side of the equation. 2b + -1c + c = 0 + c Combine like terms: -1c + c = 0 2b + 0 = 0 + c 2b = 0 + c Remove the zero: 2b = c Divide each side by '2'. b = 0.5c Simplifying b = 0.5cSolution
b = {5c, 0.5c}
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